You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Distance

A 1000 kg aut...

Question

A 1000kg automobile is moving along a straight highway at 10$ms^{-1}$. Another car with mass 2000kg and speed 20$ms^{-1}$ is 30m ahead of the first. The position of the centre of mass of the system from the first is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

30m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
20m

$x_{c m}$ = $\frac{m_{1} x_{1} + m_{2} x_{2}}{m_{1} + m_{2}} = \frac{(1000) (0) + 2000 (30)}{1000 + 2000}$

$\Rightarrow$ $x_{c m} = \frac{(2000) (30)}{3000} = 20 m$

Suggest Corrections

Similar questions

Q. A 1000 kg automobile is moving along a straight highway at

10 m s^{1}

. Another car with mass 2000kg and speed

10 m s^{1}

is 30m ahead of the first. The position of the center of mass of the system from the first is:

Q. A

1000 k g

automobile is moving along a straight highway at

10 m / s

. Another car with mass

2000 k g

is moving at speed

20 m / s

at a distance of

30 m

ahead of the first car.
Find the total momentum, using the velocity of the center of mass, compare your result with that of part.

Q. A car of mass

1000 kg

negotiates a banked curve of radius

90 m

on a frictionless road. If the banking angle is

45^{\circ}

, the speed of car is (Take

g = 10 {m/s}^{2}

)

Q. A particle

A

of mass

1 kg

moves along the line

3 x - 4 y = 0

with a speed of

10 {ms}^{- 1}

and another particle

B

of mass

2 kg

moves along the line

12 y - 5 x = 0

with a speed of

v {ms}^{- 1}

. Both of them start simultaneously from the origin, with

A

and

B

moving in first and fourth quadrants respectively, such that their center of mass is always on

x -

axis. The value of

v

Q. A

6 k g

mass moving with a velocity of

20 m s^{- 1}

collides with another

2 k g

mass moving in opposite direction with a velocity of

10 m s^{- 1}

. The momentum of system is.

Join BYJU'S Learning Program

A 1000kg automobile is moving along a straight highway at 10\(ms^{-1}\). Another car with mass 2000kg and speed 20\(ms^{-1}\) is 30m ahead of the first. The position of the centre of mass of the system from the first is

The correct option is C 20m xcm = m1x1+m2x2m1+m2=(1000)(0)+2000(30)1000+2000 ⇒ xcm=(2000)(30)3000=20m

The correct option is C
20m

$x_{c m}$ = $\frac{m_{1} x_{1} + m_{2} x_{2}}{m_{1} + m_{2}} = \frac{(1000) (0) + 2000 (30)}{1000 + 2000}$

$\Rightarrow$ $x_{c m} = \frac{(2000) (30)}{3000} = 20 m$