Question

A $100mH$ coil carries $1A$ current. Energy stored in its magnetic field is.

• A. $0.1J$
• B. $0.05J$
• C. $0.5J$
• D. $1J$

Answer 1

Answer: (B)

$0.05J$

Energy stored $E=\frac{1}{2}L{I}^2$
$=\frac{1}{2}\times 100\times {10}^{-3}\times (1{)}^2$
$=0.05J$