A 10kg wagon is pushed with a force of 7N for 1.5 second, then with a force of 5N for 1.7 seconds, and then with a force of 10N for 3 second in the same direction. What is the total change in velocity brought about?
A
9.8m/s
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B
19.6m/s
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C
4.9m/s
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D
10m/s
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Solution
The correct option is C4.9m/s change in velocity by
First force is F1t1/m=7×1.5/10=1.05m/s
by second force is F2t2/m=5×1.7/10=0.85m/s
by third force is F3t3/m=10×3/10=3m/s
Total change brought in the velocity=1.05+0.85+3=4.9m/s