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Byju's Answer

Standard XII

Chemistry

Le Chatelier's Principle for Del N Equals to 0

A 10L contain...

Question

A 10L container at 300 K contains CO $_{2}$ gas at a pressure of 0.2 atm and an excess solid CaO (neglect the volume of solid CaO). The volume of a container is now decreased by moving the movable piston fitted in the container. What will be the maximum volume of a container when a pressure of CO $_{2}$ attains its maximum value?
Given that, $C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g); K_{p} = 0.80 a t m$

5 L

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2.5 L

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1 L

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Solution

The correct option is C $2.5 L$
$K_{p} = 0.800 a t m = P_{c o_{2}} =$ maximum pressure of CO $_{2}$ in the container.

To calculate maximum volume of container $P_{c o_{2}} = 0.8$ atm and none of CO $_{2}$ should get converted into CaCO $_{3}$ (s).

So, $P V = c o n s t a n t$
$∴$ $V \times (0.800 a t m) = (10 L) \times (0.2 a t m)$
$\Rightarrow V = 2.5 L$

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The correct option is C 2.5LKp=0.800atm=Pco2= maximum pressure of CO2 in the container. To calculate maximum volume of container Pco2=0.8 atm and none of CO2 should get converted into CaCO3(s).So, PV=constant∴ V×(0.800atm)=(10L)×(0.2atm)⇒V=2.5L