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Le Chatelier's Principle for Del N Equals to 0

A 10L contain...

Question

A 10L container at 300K contains $C O_{2}$ gas at pressure of 0.2 atm and an excess solid $C a O$ (neglect the volume of solid $C a O$ ). The volume of container is now decreased bymoving themovable piston fitted in the container.What will be themaximum volume of container when pressure of $C O_{2}$ attains its maximum value given that
$C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g) K_{p} 0.800 a t m$

5 L

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2.5 L

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1 L

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The information is insufficient

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Solution

The correct option is D 2.5 L
$K_{p} = 0.800 a t m = P_{C O_{2}}$ = maximum pressure of $C O_{2}$ in the
container to calculate maximum volume of container the $P_{C O_{2}}$
$=$ 0.8 atm and none of $C O_{2}$ should get converted into $C a C O_{3} (s)$ .
so $V (0.800 a t m) = (10 L) (0.2 a t m)$
so $v = 2.5 L$

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Similar questions

10 L

300 K

C O_{2}

0.2 a t m

C a O

C a O

C O_{2}

C a C O_{3} ⇌ C a O (s) + C O_{2} (g) K_{p} = 0.800 a t m

_{2}

_{2}

C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g); K_{p} = 0.80 a t m

C O_{2 (g)}

C O_{2}

S r C O_{3 (s)} ⇌ S r O_{(s)} + C O_{2 (g)}, K_{p} = 1.6 a t m

C O_{2 (g)}

C O_{2}

S r C O_{3 (s)} ⇌ S r O_{(s)} + C O_{2 (g)}, K_{p} = 1.6 a t m

C O_{2 (g)}

S r O

C O_{2}

C O_{2}

S r C O_{3} (s) ⇌ S r O (s) + C O_{2} (g)

K p = 1.6

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