A 120V, 60Hz a.c. power is connected 800 $Ω$ non-inductive resistance and unknown capacitance in series. The voltage drop across the resistance is found to be 102V, then voltage drop across capacitor is

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102V

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63V

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55V

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Solution

The correct option is C 63V
For RC circuits,

$V^{2} = V_{R}^{2} + V_{C}^{2}$

$120^{2} = 102^{2} + V_{C}^{2}$

$V_{C}^{2} = 63.214 \approx 63 V$

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A 120V, 60Hz a.c. power is connected 800Ω non-inductive resistance and unknown capacitance in series. The voltage drop across the resistance is found to be 102V, then voltage drop across capacitor is

The correct option is C 63VFor RC circuits,V2=V2R+V2C1202=1022+V2CV2C=63.214≈ 63V

A 120V, 60Hz a.c. power is connected 800 $Ω$ non-inductive resistance and unknown capacitance in series. The voltage drop across the resistance is found to be 102V, then voltage drop across capacitor is

The correct option is C 63V
For RC circuits,

$V^{2} = V_{R}^{2} + V_{C}^{2}$

$120^{2} = 102^{2} + V_{C}^{2}$

$V_{C}^{2} = 63.214 \approx 63 V$