A 13 m ladder is leaned against a wall as shown in figure. Find the distance of foot of ladder from the wall.

1 m

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25 m

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2 m

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5 m

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Solution

The correct option is D
5 m

Distance of foot of ladder A from the wall C is AC.
Using Pythagoras theorem,
$A B^{2} = A C^{2} + B C^{2} A C^{2} = A B^{2} - B C^{2} A C^{2} = 13^{2} - 12^{2} A C^{2} = 169 - 144 A C^{2} = 25 \Rightarrow A C = 5 m$ .

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Question 128

Solve the following question:

A 5.5 m long ladder is leaned against a wall. The ladder reaches the wall to a height of 4.4 m. Find the distance between the wall and the foot of the ladder.

The angle of elevation of a ladder leaning against a wall is $60^{\circ}$ and the foot of the ladder is 9.5m away from the wall. Find the length of the ladder.

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A 13 m ladder is leaned against a wall as shown in figure. Find the distance of foot of ladder from the wall.

The correct option is D 5 m Distance of foot of ladder A from the wall C is AC. Using Pythagoras theorem, AB2=AC2+BC2AC2=AB2−BC2AC2=132−122AC2=169−144AC2=25⇒AC=5 m.

The correct option is D
5 m

Distance of foot of ladder A from the wall C is AC.
Using Pythagoras theorem,
$A B^{2} = A C^{2} + B C^{2} A C^{2} = A B^{2} - B C^{2} A C^{2} = 13^{2} - 12^{2} A C^{2} = 169 - 144 A C^{2} = 25 \Rightarrow A C = 5 m$ .