A 13 $N$ weight and 12 $N$ weight are connected by a massless string over a massless, frictionless pulley.The 13 $N$ weight has a downward acceleration with magnitude equal to that of a freely falling body, times.

1

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/ 12

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/ 13

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/ 25

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Solution

The correct option is D 1 $/ 25$
$\begin{matrix} L e t d o w n w a r d a c c e l e r a t i o n o f 13 N w e i g h t = a t h e n d o w n w a r d a c c l e r a t i o n o f 12 N w e i g h t = a L e t T = t e n s i o n i n t h e s t r i n g f o r 13 N w e i g h, 13 - T = \frac{13}{g} \times a - - - - - - - - - - (1) f o r 12 N w e i g h t, T - 12 = (\frac{12}{g}) \times a - - - - - - - - - (2) a d d i n g (1) a n d (2), 1 = \frac{25}{g} \times a o r, \frac{1}{25} = \frac{a}{g} o r, a = (\frac{1}{25}) \times g S o, \frac{1}{25} t i m e s \end{matrix}$
Hence,
option $(D)$ is correct answer.

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A 13N weight and 12N weight are connected by a massless string over a massless, frictionless pulley.The 13N weight has a downward acceleration with magnitude equal to that of a freely falling body, times.

A 13 $N$ weight and 12 $N$ weight are connected by a massless string over a massless, frictionless pulley.The 13 $N$ weight has a downward acceleration with magnitude equal to that of a freely falling body, times.