Question

A $140g$ ball, in horizontal flight with a speed of $39.0m/s$, is struck by a bat. After leaving the bat, the ball travels in the opposite direction with speed $39.0m/s.$ If the impact time for the ball-bat collision is $1.20ms$, what average force acts on the ball?

• A. 1308 N
• B. 1090 N
• C. 9100 N
• D. 980 N

Answer 1

The correct option is C 9100 N

Given,

$m=140g=0.14kg$

$u=39m/s$

$v=-u=-39m/s$

$\Delta t=1.2msec=1.2\times {10}^{-3}sec$

Impulse formula,

$I=F\times \Delta t=m(u-v)$

$F\times \Delta t=2mu$

$F=\frac{2mu}{\Delta t}=\frac{2\times 0.14\times 39}{1.2\times {10}^{-3}}$

$F=9100N$

The correct option is C.