A 1500kg car travelling east with a speed 25.0m/s collides at an intersection with a 2500−kg travelling north at a speed of 20.0m/s as shown in Figure. Find the direction and magnitude of velocity of the wreckage after the collision, assuming the vehicles stick together after the collision.
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Solution
From conservation of momentum
Initial momentum = final momentum
m→u+M→U=(m+M)→V
1500×25^i+2500×20^j=(1500+2500)→V
→V=9.375^i+12.5^j
Final velocity when they stick together is 9.375^i+12.5^j