A car of mass 1500 kg traveling at 25 m - s collides with another car B of mass 1000 kg traveling at 15 m - s in the same direction- after collision the velocity of car B will be -

Since in the question you have not provided the velocity of car A(v1), i take it as 20m/s m=mass u=initial velocity v= final velocity Now, m1= 1500kg m2=1000 ...

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Byju's Answer

Standard IX

Physics

Conservation of Momentum

a car of mass...

Question

A car of mass 1500 kg travelling at 25 m/s collides with another car B of mass 1000 kg travelling at 15 m/s in the same direction after the collision, the velocity of car B will be

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Solution

Now,
$m_{1}$ = 1500kg
$m_{2}$ =1000kg
$u_{1}$ =25m/s
$u_{2}$ =15m/s
$v_{1}$ =20m/s
$v_{2}$ =?
Law of conservation of momentum :
Formula
$m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}$
150025+100015= 1500*20+1000 $(v_{2})$
37500+15000=30000+1000 $(v_{2})$
52500=30000+1000 $(v_{2})$
52500-3000=1000 $(v_{2})$
22500=1000 $(v_{2})$
22500/1000= $(v_{2})$
$v_{2}$ = 22.5m/s

Thus, velocity of car 'B' after collision is 22.5m/s.

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