Car X of mass 200 kg moving at 5 m/s collides with car Y of mass 300 kg moving in the same direction at 3 m/s. After the collision they move off together. What is their common velocity just after the collision?

4.2 m/s

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5.6 m/s

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3.8 m/s

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7.8 m/s

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Solution

The correct option is C 3.8 m/s
Given : $m_{X} = 200$ kg $m_{Y} = 300$ kg $u_{X} = 5$ m/s $u_{Y} = 3$ m/s
Let the common velocity of the system be $V$ .
Conservation of momentum : $m_{X} u_{X} + m_{Y} u_{Y} = (m_{X} + m_{Y}) V$
$∴$ $200 (5) + 300 (3) = (200 + 300) V$ $⟹ V = 3.8$ m/s

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Car X of mass 200 kg moving at 5 m/s collides with car Y of mass 300 kg moving in the same direction at 3 m/s. After the collision they move off together. What is their common velocity just after the collision?

The correct option is C 3.8 m/sGiven : mX=200 kg mY=300 kg uX=5 m/s uY=3 m/s Let the common velocity of the system be V.Conservation of momentum : mXuX+mYuY=(mX+mY)V∴ 200(5)+300(3)=(200+300)V ⟹V=3.8 m/s

The correct option is C 3.8 m/s
Given : $m_{X} = 200$ kg $m_{Y} = 300$ kg $u_{X} = 5$ m/s $u_{Y} = 3$ m/s
Let the common velocity of the system be $V$ .
Conservation of momentum : $m_{X} u_{X} + m_{Y} u_{Y} = (m_{X} + m_{Y}) V$
$∴$ $200 (5) + 300 (3) = (200 + 300) V$ $⟹ V = 3.8$ m/s