A $1500 k g$ car travelling east with a speed $25.0 m / s$ collides at an intersection with a $2500 - k g$ travelling north at a speed of $20.0 m / s$ as shown in Figure. Find the direction and magnitude of velocity of the wreckage after the collision, assuming the vehicles stick together after the collision.

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Solution

From conservation of momentum

Initial momentum = final momentum

$m \to u + M \to U = (m + M) \to V$

$1500 \times 25^i + 2500 \times 20^j = (1500 + 2500) \to V$

$\to V = 9.375^i + 12.5^j$

Final velocity when they stick together is $9.375^i + 12.5^j$

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