A $150 g$ cricket ball moving at a speed of $12 m / s$ is hit by a bat and turned back at a speed of $20 m / s$ . The duration of impact is $0.1 s$ . What is the average force exerted on the ball by the bat?

Open in App

Solution

Average force = $\frac{Δ P}{t}$
where $Δ P$ = change in momentum
and $t$ = duration of impact.
Here , $Δ P$ = $150 (12 + 20)$ $g m s^{- 1}$
= $4.8$ $k g m s^{- 1}$
and $t$ = $0.1$ $s$
Average force exerted on the ball by the bat = $\frac{4.8}{0.1}$
= $48$ $N$

Suggest Corrections

Similar questions

Q. A cricket ball of mass

150 g

is moving with a velocity of

12 m / s

and is hit by a bat so that the ball is turned back with a velocity of

20 m / s

. The force of blow acts for

0.01 s

on the ball. The average force exerted by the bat on the ball is (in

N

)

A cricket ball of mass $150 g$ is moving with a velocity $12 m s^{- 1}$ and is hit by a bat so that the ball is turned back with a velocity of $20 m s^{- 1}$ . If the duration of contact between the ball and bat is $0.01 s$ , find the impulse and the average force exerted on the ball by the bat.

A cricket ball of mass 150 gm is moving with a velocity of 12 m/s and is hit by a bat so that the ball is turned back with a velocity of 20 m/s. The force of blow acts for 0.01s on the ball. The average force exerted by the bat on the ball is

Q. A

150 g

tennis ball coming at a speed of

40 m/s

is hit straight back by a bat to a speed of

60 m/s

. The magnitude of the average force

F

on the ball, when it is constant for

5 ms

, is:

Q. A ball of mass 0.2 kg moving with a velocity 10 m/s hits a bat normally and returns with a velocity 20 m/s. If the duration of impact is 0.01 s, find the average force exerted by the bat on the ball.

Join BYJU'S Learning Program

A 150g cricket ball moving at a speed of 12m/s is hit by a bat and turned back at a speed of 20m/s. The duration of impact is 0.1s. What is the average force exerted on the ball by the bat?

Average force = ΔPtwhere ΔP = change in momentum and t = duration of impact.Here , ΔP = 150(12+20) gms−1 = 4.8 kgms−1and t = 0.1 sAverage force exerted on the ball by the bat = 4.80.1 = 48 N

A $150 g$ cricket ball moving at a speed of $12 m / s$ is hit by a bat and turned back at a speed of $20 m / s$ . The duration of impact is $0.1 s$ . What is the average force exerted on the ball by the bat?

Average force = $\frac{Δ P}{t}$
where $Δ P$ = change in momentum
and $t$ = duration of impact.
Here , $Δ P$ = $150 (12 + 20)$ $g m s^{- 1}$
= $4.8$ $k g m s^{- 1}$
and $t$ = $0.1$ $s$
Average force exerted on the ball by the bat = $\frac{4.8}{0.1}$
= $48$ $N$