You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Chemistry

Mole Concept

A 19.6 g of...

Question

A $19.6$ g of a given gaseous sample contains $2.8$ g of molecules $(d = 0.75 g L^{- 1})$ , $11.2$ g of molecules $(d = 3 g L^{- 1})$ and $5.6$ g of molecules $(d = 1.5 g L^{- 1})$ . All density measurements are made at STP. The total number of molecules $(N)$ present in the given sample is ____ $\times 10^{23}$ .

[Take Avogardro's number as $6 \times 10^{23}$ ]

Open in App

Solution

Total weight $= 19.6 g$

a. $2.8$ g of molecules, $d = 0.765 g L^{- 1}$

Volume $= \frac{M a s s}{d} = \frac{2.8}{0.75} L$ at STP

$1 m o l \equiv 22.4 L$ at STP

Moles $= \frac{2.8}{0.75} \times \frac{1}{22.4}$

Molecules $= \frac{2.8}{0.75} \times \frac{1}{22.4} \times 6 \times 10^{23} = 1 \times 10^{23}$
b. $11.2$ g molecules, $d = 3 g L^{- 1}$

Molecules $= 1 \times 10^{23}$
c. $5.6$ g molecules, $d = 1.5 g L^{- 1}$

Molecules $= 1 \times 10^{23}$

Total number of molecules present in the given sample is $= 3 \times 10^{23}$ .

Hence, the answer is $3$ .

Suggest Corrections

Similar questions

Q. A 19.6 g of a given gaseous sample contains 2.8 g of molecules

d = 0.75 g L^{- 1}

11.2 g of molecules

(d = 3 g L^{- 1})

and 5.6 g of molecules

(d = 1.5 g L^{- 1})

. All density measurements are made at STP. Calculate the total number of molecules (N) present in the given sample. Report your answer in

N \times 10^{23}

.
Assume Avogardro's number as

6 \times 10^{23}

Q. A 19.6 g of a given gaseous sample contains 2.8 g of molecules

d = 0.75 g L^{- 1}

11.2 g of molecules

(d = 3 g L^{- 1})

and 5.6 g of molecules

(d = 1.5 g L^{- 1})

. All density measurements are made at STP. Calculate the total number of molecules (N) present in the given sample. Report your answer in

N \times 10^{23}

.
Assume Avogardro's number as

6 \times 10^{23}

Q. The total number of moles present in a gaseous mixture containing

8

g of oxygen,

11.2

L of

C O_{2}

and

3 \times

10^{22}

molecules of

N_{2}

at STP is:

The total number of moles present in a gaseous mixture containing $8 g$ of oxygen, $11.2 l i t r e s$ of $C O_{2}$ and $3 \times 10^{22}$ molecules of $N_{2}$ at STP is

Q. 12 g C-12 contains

6.022 \times 10^{23}

atoms of carbon.
(a)

6.022 \times 10^{23}

is known as .............
(b) Calculate the number of carbon atoms present in 48 g C-12.
(c) Which weighs more,

6.022 \times 10^{23}

molecules of

C O_{2}

6.022 \times 10^{23}

molecules of

H_{2} O

Join BYJU'S Learning Program