The total number of moles present in a gaseous mixture containing $8$ g of oxygen, $11.2$ L of $C O_{2}$ and $3 \times$ $10^{22}$ molecules of $N_{2}$ at STP is:

1.25

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1.05

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0.80

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0.35

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Solution

The correct option is C $0.80$
The mass of 1 mole of a gas is equal to its molecular weight.
Thus 8 grams of oxygen correspond to $\frac{8}{32} = 0.25$ moles of oxygen.

At STP, 1 mole of a gas occupies 22.4 L.
Thus 11.2 L of carbon dioxide corresponds to $\frac{11.2}{22.4} = 0.5$ moles.

1 mole of gas contains Avogadro number of molecules which is equal to $6.02 \times 10^{23}$ .
Thus $3 \times 10^{22}$ molecules of nitrogen corresponds to $\frac{3 \times 10^{22}}{6 \times 10^{23}} = 0.05$ moles.

Thus the total number of moles present is $0.25 + 0.5 + 0.05 = 0.80$ .

Hence, option C is correct.

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The total number of moles present in a gaseous mixture containing 8 g of oxygen, 11.2 L of CO2 and 3× 1022 molecules of N2 at STP is:

The total number of moles present in a gaseous mixture containing $8$ g of oxygen, $11.2$ L of $C O_{2}$ and $3 \times$ $10^{22}$ molecules of $N_{2}$ at STP is: