A 2 Kg mass is rotating on a circular path of radius 0.8 m with angular velocity of 44 rad/sec. If radius of the path becomes 1m, then what will be the value of angular velocity?

28.16 rad/sec

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19.28 rad/sec

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8.12 rad/sec

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35.26 rad/sec

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Solution

The correct option is A 28.16 rad/sec
Conservation of angular momentum
$m ω_{1} r_{1}^{2} = m ω_{2} r_{2}^{2}$
$2 \times 44 \times 0.8 \times 0.8 = 2 \times ω_{2} \times 1 \times 1 ω_{2} = 28.16 r a d / s e c$

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A 2 Kg mass is rotating on a circular path of radius 0.8 m with angular velocity of 44 rad/sec. If radius of the path becomes 1m, then what will be the value of angular velocity?

The correct option is A 28.16 rad/secConservation of angular momentum mω1r21=mω2r22 2×44×0.8×0.8=2×ω2×1×1ω2=28.16rad/sec

The correct option is A 28.16 rad/sec
Conservation of angular momentum
$m ω_{1} r_{1}^{2} = m ω_{2} r_{2}^{2}$
$2 \times 44 \times 0.8 \times 0.8 = 2 \times ω_{2} \times 1 \times 1 ω_{2} = 28.16 r a d / s e c$