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Question

# A 2 g bullet moving with a speed of 210 m/s brought to a sudden stoppage by an obstacle. The total heat produced goes to the bullet. If the specific heat of the bullet is 0.03 cal/g∘C the rise in its temperature will be

A
175C
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B
180C
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C
150C
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D
125C
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Solution

## The correct option is A 175∘CMass of bullet; m=2 g Initial velocity of bullet, v=210 m/s ∴ Initial kinetic energy of bullet =12mv2 Specific heat of bullet c=0.03 cal/g∘=0.03×4200 J/kg∘ C According to the question, kinetic energy of bullet gets converted into heat and increases the temperature (ΔT) of bullet. ∴12mv2=(mcΔT) ⇒12×2×10−3×(210)2=2×10−3×0.03×4200×ΔT ⇒ΔT=175∘ C

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