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Question

A 20-liter container at 400K contains CO2(g) at pressure 0.4 atm and an excess of SrO. The volume of the container is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when the pressure of CO2 attains its maximum value when the pressure of CO2 attains its maximum value, will be:Given that: SrCO3(s)SrO(s)+CO2(g), Kp=1.6 atm.

A
5 litre
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B
10 litre
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C
4 litre
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D
2 litre
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Solution

The correct option is A 5 litre
By using Ideal gas equation,
PV=nRT
0.4atm×20L=nCO2×R×400K
nCO2=0.2R mole Initial moles of CO2
After reaching the Equilibrium,
SrCO3(s)SrO(s)+CO2(g)
All pressure will be because of CO2 only as it is the gaseous substance.
KP=PCO2=1.6atm
P2V2=nRT
1.6atm×V2=0.2R×R×400
V2=5L
Thus when the pressure of CO2 will be maximum i.e. 1.6atm the volume will be 5L .

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