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Byju's Answer

Standard XII

Chemistry

Molarity

A 20-liter co...

Question

A 20-liter container at 400K contains $C O_{2 (g)}$ at pressure 0.4 atm and an excess of $S r O$ . The volume of the container is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when the pressure of $C O_{2}$ attains its maximum value when the pressure of $C O_{2}$ attains its maximum value, will be:Given that: $S r C O_{3} (s) ⇌ S r O (s) + C O_{2} (g)$ , $K p = 1.6$ atm.

5

litre

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10

litre

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4

litre

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2

litre

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Solution

The correct option is A $5$ litre
By using Ideal gas equation,
$P V = n R T$
$\Rightarrow 0.4 a t m \times 20 L = n_{C O_{2}} \times R \times 400 K$
$\Rightarrow n_{C O_{2}} = \frac{0.2}{R}$ mole $\Rightarrow$ Initial moles of $C O_{2}$
After reaching the Equilibrium,
$S r C O_{3} (s) ⇌ S r O (s) + C O_{2} (g)$
All pressure will be because of $C O_{2}$ only as it is the gaseous substance.
$∴ K_{P} = P_{C O_{2}} = 1.6 a t m$
$P_{2} V_{2} = n R T$
$\Rightarrow 1.6 a t m \times V_{2} = \frac{0.2}{R} \times R \times 400$
$\Rightarrow V_{2} = 5 L$
Thus when the pressure of $C O_{2}$ will be maximum i.e. $1.6 a t m$ the volume will be $5 L$ .

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