A 20 N force displaces a body by 10 m. The angle between force and direction of displacement is 60°. Calculate the work done.

100 J

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200 J

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400 J

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50 J

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Solution

The correct option is A
100 J

The angle between force and direction of displacement is 60°.
Let work done be 'W', force applied be 'F' and displacement be 'd'.
We know that,
W = F $\times$ d $\times$ cos 60° = 20 $\times$ 10 $\times$ 0.5 = 100 J.

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A body, when acted upon by a force of 10 kgf, gets displaced by 0.5 m. Calculate the work done by the force, when the displacement is (i) in the direction of force, (ii) at an angle of $60^{o}$ with the force, and (iii) normal to the force.(g=10 N $k g^{- 1}$ ).