A 20 volts ac is applied to a circuit consisting of a resistance and a coil with negligible resistance. If the voltage across the resistance is 12 V, the voltage across the coil is

16 volts

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10 volts

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8 volts

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6 volts

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Solution

The correct option is A 16 volts
The voltage across a L-R combination is given by
$V^{2} = V_{R}^{2} + V_{L}^{2}$
$V_{L} = \sqrt{V^{2} - V_{R}^{2}} = \sqrt{400 - 144} = \sqrt{256} = 16 v o l t$ .

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A 20 volts ac is applied to a circuit consisting of a resistance and a coil with negligible resistance. If the voltage across the resistance is 12 V, the voltage across the coil is

The correct option is A 16 voltsThe voltage across a L-R combination is given by V2=V2R+V2L VL=√V2−V2R=√400−144=√256=16 volt.

The correct option is A 16 volts
The voltage across a L-R combination is given by
$V^{2} = V_{R}^{2} + V_{L}^{2}$
$V_{L} = \sqrt{V^{2} - V_{R}^{2}} = \sqrt{400 - 144} = \sqrt{256} = 16 v o l t$ .