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Standard XII

Chemistry

Nernst Equation

A 200 W, 110 ...

Question

A 200 W, 110 V incandescent lamp is connected in series with an electrolytic cell of negligible resistance containing a solution of $Z n C l_{2}$ . What weight of Zn will be deposited from the solution on passing current for 30 minutes? (Atomic weight of Zn = 65.4)

2.2 gm

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1.1 gm

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0.505 gm

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4.4 gm

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Solution

The correct option is B 1.1 gm
$C u r r e n t, I = \frac{W a t t}{V o l t} = \frac{200 W}{110 V} = 1.818 A$
The quantity of electricity passed $= Q (C) = 1.818 A \times 30 \times 60 s = 3272.72 C$
Atomic weight of zinc $=$ 65.4 gm/mol
Moles of electrons passed $= \frac{Q (C)}{96500 \frac{C}{m o l e^{-}}} = \frac{3272.72 C}{96500 \frac{C}{m o l e^{-}}} = 0.0339 m o l e^{-}$
The weight of zinc deposited $= m o l a r m a s s o f Z n \times m o l e r a t i o \times m o l e s o f e l e c t r o n s p a s s e d$
$= 65.4 \frac{g}{m o l} \times \frac{1 m o l Z n}{2 m o l e^{-}} \times 0.0339 m o l e^{-} = 1.1 g m$

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A 200 W, 110 V incandescent lamp is connected in series with an electrolytic cell of negligible resistance containing a solution of ZnCl2. What weight of Zn will be deposited from the solution on passing current for 30 minutes? (Atomic weight of Zn = 65.4)

A 200 W, 110 V incandescent lamp is connected in series with an electrolytic cell of negligible resistance containing a solution of $Z n C l_{2}$ . What weight of Zn will be deposited from the solution on passing current for 30 minutes? (Atomic weight of Zn = 65.4)