Question

A 100 W, 110-V incandescent lamp is connected in series with an electrolytic cell containing cadium sulphate solution. The amount of cadium (in gm) that will be deposited by the current flowing for 10 h is: (write your answer to nearest integer)

Answer 1

$Watt=Ampere\times Volt$

$\therefore Ampere\left(i\right)=\frac{Watt}{Volt}=\frac{100}{110}$

Now, $W=\frac{Zlt}{96500}$

$\therefore W_{Cd}=\frac{112.4\times 100\times 10\times 60\times 60}{2\times 110\times 96500}$

$=\frac{404640000}{21230000}=19.06g$