A $220 V$ , $1000 W$ bulb is connected across a $110 V$ main supply. The power consumed will be

1000 W

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750 W

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500 W

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250 W

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Solution

The correct option is C $250 W$
Power, $P = V^{2} / R$
so the resistance of bulb is $R = V^{2} / P = \frac{220^{2}}{1000} = 48.4 Ω$

Power consumed $= \frac{V_{m}^{2}}{R} = \frac{110^{2}}{48.4} = 250 W$

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A 220V, 1000W bulb is connected across a 110V main supply. The power consumed will be

The correct option is C 250WPower, P=V2/Rso the resistance of bulb is R=V2/P=22021000=48.4ΩPower consumed =V2mR=110248.4=250W

A $220 V$ , $1000 W$ bulb is connected across a $110 V$ main supply. The power consumed will be

The correct option is C $250 W$
Power, $P = V^{2} / R$
so the resistance of bulb is $R = V^{2} / P = \frac{220^{2}}{1000} = 48.4 Ω$

Power consumed $= \frac{V_{m}^{2}}{R} = \frac{110^{2}}{48.4} = 250 W$