A 250 g block slides on a rough horizontal table. Find the work done by the frictional force in bringing the block to rest if it is initially moving at a speed of 40 cm/s. If the friction coefficient between the table and the block is 0.1, how for does the block move before coming to rest?
Given, m=250 gm=0.250 kg
u=40 cm/sec
=0.4 m/sec,μ=0.1,v=0
Here, μR=ma
(where a is deceleration)
a=(μRm)=(μ mgm)=μ g
=0.1×9.8=0.98 m/s2
s=v2−u22a=0.082 m
=8.2 cm