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Question

A 2kg block is placed over a 4kg block and both are placed on a smooth horizontal surface. The coefficient of friction between the blocks is 0.20. The acceleration of the two blocks if a horizontal force of 12N is applied to the upper block (g=10ms−2)

A
4ms2,2ms2
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B
2ms2,2ms2
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C
3ms2,3ms2
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D
4ms2,1ms2
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Solution

The correct option is C 4ms2,1ms2
The correct option is D.

Given,

masses=2kg,4kg

Coefficient 0.20

Force =12N

R12g=0

R1=2x10=20

2a+0.2R112=0

2a+0.2(20)=12

2a=124

a=4m/.s2

Again,

4aμR1=0.2(20)=4

a1=1m/s2

2kg block has acceleration 4m/s2 and that of 4kg is 1m/s2

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