Question

A $2V$ battery, a$990\Omega$ resistor and a potentiometer of $2m$ length, all are connected in series of the resistance of potentiometer wire is $10\Omega$, then the potential gradient of the potentiometer wire is

• A. $0.05V{m}^{-1}$
• B. $0.5V{m}^{-1}$
• C. $0.01V{m}^{-1}$
• D. $0.001V{m}^{-1}$

Answer 1

Answer: (C)

$0.01V{m}^{-1}$

Potential gradient $x=\frac{e}{(R+R_h+r)}\cdot \frac{R}{L}$
$\Rightarrow x=\frac{2}{(990+10)}\times \frac{10}{2}=0.01V{m}^{-1}$