Question

A 3-d transition metal cation $x^{3+}$ has magnetic moment $\sqrt{35}$ BM. What is the atomic number of metal $x$?

• A. 24
• B. 25
• C. 26
• D. 27

Answer 1

Answer: (C)

26

Magnetic moment$=\sqrt{n(n+2)}B.M.$ where $n=$ no. of unpaired electrons.

$\therefore 35=n(n+2)$

$\therefore n=5$

$\therefore x^{3+}$ ion has $5$ unpaired electrons i.e.it may have $5$ unpaired electrons in third orbital.

$\therefore$ Total no. of electrons$=26$