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Question

A 3μF capacitor is charged to a potential of 300 V and 2μF capacitor is charged to 200 V. The capacitors are then connected in parallel with plates of opposite polarities joined together. What amount of charge will flow, when the plates are so connected?

A
1300 μC
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B
800 μC
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C
600 μC
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D
300 μC
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Solution

The correct option is A 1300 μC
Whenever a capacitor is charged by a well-defined Potential, the charge accumulated by it is given by Q=CV

The charge stored in 1st capacitor is 3μF×300V=3×106×300=9×104coulombs

The charge stored in 2nd capacitor is 2μF×200V=2×106×200=4×104coulombs

When they are connected in parallel with opposite polarities, the charges will get neutralized until the total charge remains the difference between them.
Each capacitor will have the half of the total charge.

total charge=(94)×104=5×104
Thus both the capacitors will have 2.5×104coulombs.

Since current always flows from a higher potential to a lower potential, we can say that charges will flow from the 1st capacitor to the 2nd.

Initially, 4×104coulombs of charge will flow to neutralize the charge on the 2nd capacitor. The 1st capacitor will now have 5×104 C and 2nd will be chargeless.
Thereafter 2.5×104C will flow from 1st to 2nd.

Thus total 6.5×104 coulombs of charge will flow from the 1st capacitor to the 2nd one.

Answer:- 650μC

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