A 300 g mass has a velocity of (3^i+4^j)m/s at a certain instant. What is its kinetic energy?
1.35 J
2.4 J
3.75 J
7.35 J
→v=(3^i+4^j)∴speed=v=√32+42=5m/s. So kinetic energy = 12mv2=12×0.3×(5)2=3.75J
A 300 g mass has a velocity of (3^i+4^j)m/s at a certain instant. What is its kinetic energy
A body having 5 kg mass is traveling with a certain velocity and has 10 kgms−1 momentum. What will be its kinetic energy?