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Question

a4-b2+12expand it with suitable identities .


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Solution

Solve the given identity : Here we use the identity (x+y+z)2=x2+y2+z2+2xy+2yz+2zx

Now we have x=a4,y=-b2,z=1

So (a4-b2+1)2=(a4)2+(-b2)2+12+2×a4×(-b2)+2(-b2)×1+2×1×(a4)

=a216+b24+1-ab4-b+a2

Hence (a4-b2+1)2=a216+b24+1-ab4-b+a2


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