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Second Law of Motion

A 4-kilograms...

Question

A 4-kilograms ball slides over horizontal friction less surface with velocity of 1 meter per second ball strike the post and rebounds upward perpendicular to the initial direction with same speed.
Calculate the change of momentum of the ball in initial direction.

A

-4 kg.m/s

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B

-1 kg.m/s

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C

0 kg.m/s

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D

1 kg.m/s

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E

4 kg.m/s

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Solution

The correct option is A -4 kg.m/s
Initially the velocity of the ball in horizontal direction is $1 m / s$ .
Finally the velocity of ball remains in vertical direction. Thus velocity in initial direction(horizontal)= $0 m / s$
Thus the change in momentum= $_{2} -_{1} = m (_{2} -_{1}) = 4 \times (0 - 1) k g m / s = - 4 k g m / s$

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