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Equivalent Mass

A 4 M , 500 m...

Question

A $4 M$ , $500 m L$ aqueous solution containing $M^{1 +}$ is made to react with $1 M, 1 L$ $H N O_{3} .$ As a result, some of $M^{1 +}$ is converted into $M^{x +}$ and all $H N O_{3}$ into NO(g). After the reaction concentration of $M^{x +}$ ions becomes $\frac{1}{3} M$ value of X is:

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Solution

$M^{+ 1} + + 5 H N O_{3} \to M^{x +} + + 2 N O$
$\begin{matrix} n f = (x - 1) & n f = 3 & n f = (x - 1) 2 m o l & 1 m o l & 1 m o l 1 m o l \end{matrix}$
Total volume = 1 + 0.5 = 1.5 L
eq. of $M^{x +} = e q . o f H N O_{3}$
$M \times n f \times V = M \times n f \times V$
$\frac{1}{3} \times (x - 1) \times 1.5 = 1 \times 3 \times 1$
$(x - 1) = 6 \Rightarrow x = 7$

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