What is the concentration of chloride ion in the mixture of $500 m l, 1 M N a C l$ solution and $500 m l, 1 M C a C l_{2}$ solution?

2.5

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1.5

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Solution

The correct option is C 1.5
Mole of $N a C l$ = $\frac{500}{1000} \times 1$ = 0.5 mol $N a C l$ or 0.5 mol $C l^{-}$ ions

Mole of $C a C l_{2}$ = $\frac{500}{1000} \times 1$ = 0.5 mol $C a C l_{2}$ or 1 mole of $C l^{-}$ ions

Total mole of $C l^{-}$ ion 0.5 + 1 = 1.5 mol
Total volume = 500 ml + 500 ml = 1000 ml or 1 L
So concentration of $C l^{-}$ ion is 1.5 in 1000 mL.

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