CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
72
You visited us 72 times! Enjoying our articles? Unlock Full Access!
Question

Find the molarity of the Cl− ion in the resulting solution form by mixing 500ml of 1M NaCl and 500ml 1M HNO3.

A
0.5 M
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.8 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.4 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1 M
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.5 M
Given that,
Volume of NaCl, V1= 500 ml
Volume of HNO3, V2= 500 ml
Total volume, V= 1000 ml

Now,
Molarity of Cl ion =M1×V1V=1×5001000=0.5 M

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Reactions in Solutions
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon