A - 4n - 3n - 1-n - B - 9n - 1- n - then A - B is

Name: JEE- Grade 11- Mathematics- Fundamentals of Mathematics 11- Session 11- D05
Uploaded: 2022-07-04T10:36:42+05:30
Description: A = {0, 9, 54,...} B = {0, 9, 18, 27,...} ⇒ A ∩ B = A ...

A = {0, 9, 54,...} B = {0, 9, 18, 27,...} ⇒ A ∩ B = A ...

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Byju's Answer

Standard XIII

Mathematics

Intersection

A = 4n − 3n −...

Question

$A = {(4^{n} - 3 n - 1) | n \in N},$ $B = {9 (n - 1) | n \in N},$ then $A \cap B$ is

A

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B

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N

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ϕ

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Solution

The correct option is A $A$
$A = {0, 9, 54, . . .} B = {0, 9, 18, 27, . . .} \Rightarrow A \cap B = A$

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Similar questions

A = {(4^{n} - 3 n - 1) | n \in N},

B = {9 (n - 1) | n \in N},

then

A \cap B

Q. If

A = {4^{n} - 3 n - 1 : n \in N}

and

B = {9 (n - 1) : n \in N}

, then?

A = {(4^{n} - 3 n - 1) | n \in N},

B = {9 (n - 1) | n \in N},

then

A \cap B

Q. Let

U = {x \in N ∣ x < 20}

be the universal set. Let

A = {x \in N ∣ x is prime less than 20}

B = {x \in N ∣ x is 3 n, n \in N, n \leq 6}

C = {x \in N ∣ x = 2 n - 1, n \in N, n \leq 10}

. Then

n [(A \cup B)^{'} \cup (A \cap C)] =

Q. If

X = {4^{n} - 3 n - 1; n \in R}

and

Y = {9 (n - 1); n \in N}

, then

X \cap Y =

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Intersection

Standard XIII Mathematics

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A={(4n−3n−1)|n∈N}, B={9(n−1)|n∈N}, then A∩B is

The correct option is A AA={0,9,54,...}B={0,9,18,27,...}⇒A∩B=A

$A = {(4^{n} - 3 n - 1) | n \in N},$ $B = {9 (n - 1) | n \in N},$ then $A \cap B$ is

The correct option is A $A$
$A = {0, 9, 54, . . .} B = {0, 9, 18, 27, . . .} \Rightarrow A \cap B = A$