A 4 - resistor in series with 8 - resistance are connected to 12V supply- If another resistor of 8 - is connected across the 8 - resistor the current drawn from source would be -

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Combination of Resistors

A 4 Ω resist...

Question

A 4 $Ω$ resistor in series with 8 $Ω$ resistance are connected to 12V supply. If another resistor of 8 $Ω$ is connected across the 8 $Ω$ resistor the current drawn from source would be :

Increases by 25%

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Decreases by 5%

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Increases by 50%

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Decreasesby 50%

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Solution

The correct option is C Increases by 50%
$R_{e q} = 4 + 4 = 8 Ω$
$I = \frac{12}{8} = 3 / 2$
$=$ $1.5 A$
$\Rightarrow$ I increased by $50 %$

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A 4Ω resistor in series with 8Ω resistance are connected to 12V supply. If another resistor of 8Ω is connected across the 8Ω resistor the current drawn from source would be :

The correct option is C Increases by 50%Req=4+4=8ΩI=128=3/2= 1.5A⇒ I increased by 50%

A 4 $Ω$ resistor in series with 8 $Ω$ resistance are connected to 12V supply. If another resistor of 8 $Ω$ is connected across the 8 $Ω$ resistor the current drawn from source would be :

The correct option is C Increases by 50%
$R_{e q} = 4 + 4 = 8 Ω$
$I = \frac{12}{8} = 3 / 2$
$=$ $1.5 A$
$\Rightarrow$ I increased by $50 %$