Question

# A battery of 10 V is connected in series with resistors of 3 Ω,5 Ω,4 Ω,5 Ω and 13 Ω. How much current would flow through the 3 Ω resistor?

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Solution

## 10 V is connected in series with resistors of 3 Ω,5 Ω,4 Ω,5 Ω and 13 Ω. so, Req=3+5+4+5+13=30 Ω We know from ohms law I=VR=1030=0.33A Same current will flow from all the resistances.

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