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Question

# A 5 V battery with internal resistance 2 Ω and a 2 V battery with , internal resistance 1Ω are connected to a 10 Ω resistor as shown in the figure.The current in the 10Ω resistor is

A
0.03AP1 to P2
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B
0.03AP2 to P1
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C
0.27AP1 to P2
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D
0.27AP2 to P1
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Solution

## The correct option is B 0.03AP2 to P1ApplyingKirchhoff′slawfortheloopsAP2P1CAandp2BDp1p2.−10y−2x+5=0⇒2x+10y=5..............(1)=2−1(x−y)+10.y=0⇒x−11y=2.............(2)2x−22y=4..............(3)from(1)&(3)gives32y=1⇒y=132A=0.03Afromp2top1.

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