CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A 5 V battery with internal resistance 2 Ω and a 2 V battery with internal resistance 1 Ω are connected to a resistor as shown in the figure.


The current in the resistor is

A
0.27 A,P2 to P1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.03 A,P1 to P2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.03 A,P2 to P1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
0.27 A,P1 to P2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 0.03 A,P2 to P1
Let potential at P1 is 0 V and potetial at P2 is V0. Now apply KCL at P2.


V052+V0010+V0(2)1=0

V0=516

So, current through 10 Ω resistor is, V=IR (Ohm's law)

I=ΔVR=51610=132 A

or I=0.031250.03 A

(From P2 to P1)

flag
Suggest Corrections
thumbs-up
18
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon