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Sinusoidal AC

A 400 Ω ele...

Question

A 400 $Ω$ electric heater is connected to a 200 V, 50 Hz mains supply. The peak
value of electric current flowing in the circuit is approximately

A

2.5 amp

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B

5.0 amp

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C

0.7 amp

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D

10 amp

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Solution

The correct option is C 0.7 amp
200V is the rms value of the potential difference. So the peak value of the voltage is $200 \sqrt{2}$ .
Thus, peak value of current = $\frac{200 \sqrt{2}}{400} = 0.7 a m p$

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