H2O2+H2SO4+2KI⟶K2SO4+I2+2H2O
We know,
Molar mass of H2O2=34 g
Molar mass of I2=254 g
So, 254 g of I2 is obtained from 34 g H2O2
0.508 g of I2 is obtained from 34254×0.508 g H2O2=0.068 g H2O2
5 mL of the solution contains=0.068 g H2O2
1 mL of the solution contains=0.0685 g H2O2=0.0136 g H2O2
2H2O268 g⟶2H2O+O222400 mL
68 g of H2O2 produces 22400 mL O2
0.0136 g of H2O2 will produce=2240068×0.0136 mL of O2=4.48 mL ofO2
1 mL of H2O2 solution gives 4.48 mL of oxygen
So, strength of H2O2 solution = 4.48 V