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Question

A 5.0 cm3 solution of H2O2 liberates 0.508 g of iodine from acidified KI solution. Calculate the strength of H2O2 solution in terms of volume strength at STP.

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Solution

H2O2+H2SO4+2KIK2SO4+I2+2H2O
We know,
Molar mass of H2O2=34 g
Molar mass of I2=254 g

So, 254 g of I2 is obtained from 34 g H2O2
0.508 g of I2 is obtained from 34254×0.508 g H2O2=0.068 g H2O2

5 mL of the solution contains=0.068 g H2O2
1 mL of the solution contains=0.0685 g H2O2=0.0136 g H2O2

2H2O268 g2H2O+O222400 mL
68 g of H2O2 produces 22400 mL O2
0.0136 g of H2O2 will produce=2240068×0.0136 mL of O2=4.48 mL ofO2

1 mL of H2O2 solution gives 4.48 mL of oxygen
So, strength of H2O2 solution = 4.48 V

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