A 5-ampere fuse wire can withstand a maximum power of 1 watt in the circuit. The resistance of the fuse wire is :

5 ohm

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0.04 ohm

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0.2 ohm

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0.4 ohm

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Solution

The correct option is C 0.04 ohm
We know that
$P = I^{2} R \Rightarrow R = \frac{P}{I^{2}} = \frac{1}{25} = 0.04 Ω$

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A 5-ampere fuse wire can withstand a maximum power of 1 watt in the circuit. The resistance of the fuse wire is :

The correct option is C 0.04 ohmWe know that P=I2R⇒R=PI2=125=0.04Ω

The correct option is C 0.04 ohm
We know that
$P = I^{2} R \Rightarrow R = \frac{P}{I^{2}} = \frac{1}{25} = 0.04 Ω$