Question

A 5 ampere wire can withstand a maximum power of 1 watt in the circuit. The resistance of the fuse wire is

• A. $0.004\Omega$
• B. $0.2\Omega$
• C. $5\Omega$
• D. $0.4\Omega$

Answer 1

Answer: (A)

$0.004\Omega$

We knew that $I^{2}R=P$ the maximum power that wire can withstand is 1 watt.

the current that can be withstand by wire is 5 Amp

hence using the formula given above , by putting vaplues of currrent and power we get , $R=\frac{1}{25}=0.004\Omega$