A 5 g piece of ice at $- 20^{\circ}$ C is put into 10 g of water at $30^{\circ}$ C. Assuming that heat is exchanged only between the ice and the water. Then find the heat required for phase change. Specific heat capacity of ice $= 2100 J k g^{- 1}^{\circ} C^{- 1}$ . Specific heat capacity of water $= 4200 J k g^{- 1}^{\circ} C^{- 1}$ and latent heat of fusion of ice $3.36 \times 10^{5} J k g^{- 1}$ .

$1680 J$

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$2680 J$

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$3680 J$

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$4680 J$

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Solution

The correct option is A
$1680 J$

Heat gives by water $(30^{\circ} C) = 0.01 \times 4200 \times 30 = 1260 J$
Heat required to bring the ice to $0^{\circ} C$
$= 0.005 \times 2100 \times 20 = 210 J$

Heat required for phase change = $0.005 \times 3.36 \times 10^{5}$ = $1680 J$

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A 5 g piece of ice at $- 20^{\circ} C$ is put into 10 g of water at $30^{\circ} C$ . Assuming that heat is exchanged only between the ice and the water, find the final temperature of the mixture. Specific heat capacity of ice = $2100 J k g^{- 1}$ $^{\circ} C^{- 1}$ , specific heat capacity of water = $4200 J k g^{- 1}$ $^{\circ} C^{- 1}$ and latent heat of fusion of ice = $3.36 \times 10^{5} J k g^{- 1}$ .

Q. A 5g piece of ice at

- 20^{\circ}

C is put into 10g of water at

30^{\circ}

C. Assuming that heat is enchanged only between the ice and the water, find the final temperature of the mixture. Specific heat capacity of ice

= 2100 J k g^{- 1}^{\circ} C^{- 1}

. Specific heat capacity of water

= 4200 J k g^{- 1}^{\circ} C^{- 1}

and latent heat of fusion of ice

3.36 \times 10^{5} J k g^{- 1}

Calculate the amount of heat required to convert 1.00 kg of ice at -10°C at normal pressure to steam at 100°C. Specific heat capacity of ice = 2100 J kg⁻¹ K⁻¹ , latent heat of fusion of ice = 3.36 × 10⁵ J kg⁻¹ , specific heat capacity of water = 4200 J kg ⁻¹ K⁻¹ and latent heat of vaporization of water = 2.25 × 10⁶ J kg⁻¹

The amount of heat energy required to convert 1 kg of ice at $- 10^{\circ} C$ to water at $100^{\circ} C$ is 7,77,000 J. Calculate the specific latent heat of ice.

Specific heat capacity of ice = 2100 J $k g^{- 1} K^{- 1}$ , specific heat capacity of water=4200 J k $g^{- 1} K^{- 1}$ .

10 g of ice at $0^{o} C$ absorbs 5460 J of heat energy to melt and change to water at $50^{o} C$ . Calculate the specific latent heat of fusion of ice. Specific heat capacity of water is 4200 J $k g^{-} 1 K^{- 1}$ .

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The correct option is A 1680 J Heat gives by water (30∘ C)=0.01×4200×30=1260 J Heat required to bring the ice to 0∘ C =0.005×2100×20=210 J Heat required for phase change = 0.005×3.36×105 = 1680 J

The correct option is A
$1680 J$

Heat gives by water $(30^{\circ} C) = 0.01 \times 4200 \times 30 = 1260 J$
Heat required to bring the ice to $0^{\circ} C$
$= 0.005 \times 2100 \times 20 = 210 J$

Heat required for phase change = $0.005 \times 3.36 \times 10^{5}$ = $1680 J$