Question

A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find at the same time the length of the shadow cast by another pole 10 m 50 cm high.

Answer 1

Here height of the pole and length of the shadow are in direct proportion.
And $1m=100cm5m60cm=5\times 100+60=560cm3m20cm=3\times 100+20=320cm10m50cm=10\times 100+50=1050cm$

Let the length of the shadow of another pole be x.
$\begin{array}{ccc}Heightofpole\left(incm\right)& 560& 1050\\ Lengthofshadow\left(incm\right)& 320& x\end{array}$

Here the length of the pole and the length of its shadow are in direct proportion.

$\therefore \frac{560}{320}=\frac{1050}{x}\Rightarrow x\times 560=1050\times 320\Rightarrow x=\frac{1050\times 320}{560}=600cm=6m$

Hence, the length of the shadow of another pole is 6 m.