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Ideal Gas Equation

A 5 ml solu...

Question

A $5$ ml solution of $H_{2} O_{2}$ liberates $0.508$ g of iodine from an acidified $K I$ solution. What is the volume strength of the $H_{2} O_{2}$ solution?

A

2.2 %

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B

3.8 %

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C

4.48 %

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D

None of the above

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Solution

The correct option is D None of the above
Meq of $H_{2} O_{2} =$ M eq of $I_{2}$ (Iodine molecule)
$\frac{W}{34} \times 1000 = \frac{0.508}{(254 / 2)} \times 1000$
Now on calculation for W:
$W = 0.136$ g
As $H_{2} O_{2} \to H_{2} O + \frac{1}{2} O_{2}$
As $34$ g $H_{2} O$ gives $11.2$ litre $O_{2}$
Thus, $0.136$ g of $H_{2} O_{2}$ will give = $\frac{11.2}{34} \times 0.136 = 0.0448$ litre $= 44.8$ mL
So volume strength of $H_{2} O_{2}$ is $\frac{44.8 m L}{5 m L} = 8.96$ %

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