Question

A 5 $\mu F$ capacitor is connected in series with a 10 $\mu F$ capacitor. When a 300 Volt potential difference is applied across this combination, the energy stored in the capacitors is.

• A. 15 J
• B. 1.5 J
• C. 0.15 J
• D. 0.10 J

Answer 1

The correct option is C 0.15 J

The equivalent capacitance of the combination of the capacitors=$\frac{C_1{C}_2}{C_1+C_2}$

$=\frac{10}{3}\mu F$

Hence the energy stored in the capacitors=$\frac{1}{2}{C}_{eff}{V}^2$

$=\frac{1}{2}\times \frac{10}{3}\times {10}^{-6}\times {300}^{2}J$

$=0.15J$