A 50 gm ball collides with another ball of mass 150gm, moving in its direction of motion, After collision the two balls move at a an angle $30^{0}$ with their initial direction. Ratio of their velocities after collision is

3 : 1

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1 : 3

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2 : 3

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1 : 1

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Solution

The correct option is C 3 : 1
The momentum of the system is conserved in every direction. Since the initial vertical momentum is zero, the final vertical momentum is also zero.
Therefore,
$50 v_{1} \times s i n 30^{\circ} = 150 v_{2} \times s i n 30^{\circ}$

$\frac{v_{1}}{v_{2}} = \frac{3}{1}$ .

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A 50 gm ball collides with another ball of mass 150gm, moving in its direction of motion, After collision the two balls move at a an angle 300 with their initial direction. Ratio of their velocities after collision is

The correct option is C 3 : 1The momentum of the system is conserved in every direction. Since the initial vertical momentum is zero, the final vertical momentum is also zero.Therefore,50v1×sin30∘=150v2×sin30∘v1v2=31.

A 50 gm ball collides with another ball of mass 150gm, moving in its direction of motion, After collision the two balls move at a an angle $30^{0}$ with their initial direction. Ratio of their velocities after collision is

The correct option is C 3 : 1
The momentum of the system is conserved in every direction. Since the initial vertical momentum is zero, the final vertical momentum is also zero.
Therefore,
$50 v_{1} \times s i n 30^{\circ} = 150 v_{2} \times s i n 30^{\circ}$

$\frac{v_{1}}{v_{2}} = \frac{3}{1}$ .