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Question

A 50 kg boy stands on a platform spring scale in a lift that is going down with a constant speed 3 m/s. If the lift is brought to rest by a constant deceleration in a distance of 9 m, what does the scale read (in Newtons) during this period ? (g=9.8 m/s2) 


Solution

Using the 3rd equation of motion
v2=u2+2as
Taking downward direction as positive, 
0=(3)22(a)(9)
   a=12=0.5 m/s2      (upwards)
N=m(g+a)
=50(9.8+0.5)=515 N

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